# You asked: How many moles of oxygen are needed for the complete combustion of 3 0 moles of ch4 g )?

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## How many moles of oxygen ate needed for the complete combustion of two moles of butane?

C4H10 + 6.5 O2 → 4 CO2 + 5 H2O. Each mole of butane needs 6.5 moles of oxygen, so 13 moles of oxygen is required for 2 moles of butane in a complete combustion.

## How many moles of O2 are required for the complete combustion?

Mass of oxygen required = 19.5 moles × 16 g/mol = 312 g. Hence, 312 grams of oxygen is essentially required for complete combustion of 3 moles of butane gas.

## How many moles of oxygen are required for the complete combustion of 1 mole of ethene?

This means that, in order for the reaction to take place, every mole of the former will require 9 moles of the latter.

## How many moles of O2 are needed to produce 5 Moles h2o?

From this you can see that 5 moles of hydrogen gas would react with 2.5 of the available 3 moles of oxygen gas, to form 5 moles of water. The molar mass of water is 18 g/mol, so you would end up with 5 x 18 = 90 g of water.

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## How many grams of oxygen are required for the complete combustion of 2 moles of benzene?

So we can say that for the combustion of benzene 2 moles of benzene is required, 15 moles of oxygen molecule is required, and after combustion we get 12 moles of carbon dioxide and 6 moles of water. Now we all know that the volume of one mole of gas at STP is 22.4 liter.

## How much air is required for combustion?

1 kg of carbon requires 8/3 kg of oxygen for its complete combustion; therefore C kg of carbon will require C x 8/3 kg of oxygen which is equivalent to 2.66C kg of oxygen (considering upto two places of decimal).

## How many moles of electrons weigh 1kg?

Or, 1 kg will contain = \$dfrac{1}{{9.108 times 6.022}} times {10^8}\$ moles of electrons. Thus, \$dfrac{1}{{9.108 times 6.022}} times {10^8}\$ moles of electrons will weigh one kilogram. So, the correct answer is “Option D”.