# Best answer: How many moles of NaOH are required to neutralize HCl?

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## How many moles are needed to neutralize?

So, the solution will be neutralized when the number of moles of H+ equals the number of moles of OH.

1. Step 1: Calculate the number of moles of OH.
2. Molarity = moles/volume.
3. moles = Molarity x Volume.
4. moles OH = 0.02 M/100 milliliters.
5. moles OH = 0.02 M/0.1 liters.
6. moles OH = 0.002 moles.

## What is the neutralization equation between HCl and NaOH?

The products of such a reaction are typically water and a salt. The balanced chemical equation representing the neutralization of hydrochloric acid with sodium hydroxide is: HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l) + heat.

## How many moles are in NaOH?

Determining the Molar Mass of a Compound

The molar mass of the compound NaOH is 40 g/mol.

## How many moles of NaOH were used in the titration?

Since 30 ml (or 0.03 liters) of NaOH was used for the titration, 0.03 liters · 0.1 moles/liter = 0.003 moles of NaOH was used to titrate the HCl. Since the mole ratio is 1:1, the same number of moles (0.003) of HCl must have been titrated.

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## Does NaOH neutralize HCl?

The reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) is a neutralization reaction which results in the formation of a salt, sodium chloride (NaCl) , and water (H2O) . It is an exothermic reaction.

## How is HCl neutralized?

An acid must be neutralized with a base, which, by definition, is characterized by an excess of OH- ions. … For example: In a simple neutralization process hydrochloric acid (HCl) can be neutralized by using sodium hydroxide (NaOH).

## When NaOH neutralizes HCl in solution what substances are produced?

Let’s see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl → H2O and NaCl. Now let’s break this reaction down into two parts to see how each product forms.

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## How many grams of H3PO4 is required to completely neutralize 120g of NaOH?

Therefore 98g of H3PO4 is required to completely neutralise 120g of NaOH.